Ex 6.1, 12 - Chapter 6 Class 11 Linear Inequalities (Term 2)
Last updated at Dec. 8, 2016 by Teachoo
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 6.1, 12 Solve the given inequality for real x: 1 2 3 5 +4 1 3 (x 6) 1 2 3 5 +4 1 3 (x 6) 3 3 5 +4 2 (x 6) 3 3 5 + 3 4 2x 2 6 9 5 + 12 2x 12 9 5 2x 12 12 9 5(2 ) 5 24 9 10 5 24 5 24 24 5 120 Since x is negative, we multiply both sides by -1 & change the signs ( 1) ( x) ( 1) ( 120) x 120 Hence, x is a real number which is less than or equal to 120 Hence, x ( 120] is the solution
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