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Suppose we have one octal number. We have to check whether the decimal representation of the given octal number is divisible by 7 or not.

So, if the input is like n = 61, then the output will be True as the decimal representation of 61 is 6*8 + 1 = 48 + 1 = 49 which is divisible by 7.So, if the input is like n = 61, then the output will be True as the decimal representation of 61 is 6*8 + 1 = 48 + 1 = 49 which is divisible by 7.

To solve this, we will follow these steps −

- sum := 0
- while num is non-zero, do
- sum := sum + (num mod 10)
- num := quotient of (num / 10)

- if sum mod 7 is same as 0, then
- return True

- return False

Let us see the following implementation to get better understanding −

def solve(num): sum = 0 while num: sum += num % 10 num = num // 10 if sum % 7 == 0 : return True return False num = 61 print(solve(num))

61

True

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